The ratio of your TPA to your opponent's TPA will determine

[khronosschoty]

The ratio of your TPA to your opponent's TPA will determine the success rate of your conducted thievery ops.

Does anyone have a more concrete example of this?

[Palem]

You mean like the exact success rate formula?

or just examples of how this works?

[noobium]

It means exactly that - the ratio of tpa to tpa determines the base success rate of thief ops.
Typically a 4:1 tpa advantage is necessary for consistent success on most ops, 3:1 for easier ops.

[Thinkorswim]

Is it straight up tpa ratio for op success? Using your example of 4:1 tpa advantage, 4 success for every 1 fail, or is it more complicated.

[noobium]

Is it straight up tpa ratio for op success? Using your example of 4:1 tpa advantage, 4 success for every 1 fail, or is it more complicated.

It is more complicated, varies based on the op and thieves sent (?), and the exact success rate calculation has never been revealed.

[khronosschoty]

I wonder why they make the calculation rate known for attackers but us thieves are left in the dark? I want some solid factual math about how many more mod TPA thieves I need to have to get say 99% success rate.

[Palem]

They didn't let anyone know anything.

Players constructed the attack formulas.

[StratOcastle]

Yeah, even with formulas I was eyeballing attacks 4 ages ago. I stink at math and I saw guys with formulas bounce.

Oh, and cool avatar, long named guy with a 'k' in it.

[khronosschoty]

I say, and ask, they should release the formulas :D

Yeah, even with formulas I was eyeballing attacks 4 ages ago. I stink at math and I saw guys with formulas bounce.

Oh, and cool avatar, long named guy with a 'k' in it.

thanks man

[Palem]

Why?

If you want a formula, figure it out lol